Answer to Question #102452 in Mechanics | Relativity for Akshay

Question

A plane is flying with a constant speed along a straight line at an angle of 30
with the horizontal. The weight of the plane is 100000 N and its engine provides
a thrust of 120000 N in the direction of flight. Two additional forces are exerted
on the plane: the lift force perpendicular to the plane’s wings, and the force due
to air resistance opposite to the direction of motion. Draw the free-body diagram
showing all forces on the plane. Determine the lift force and the force due to air
resistance

Answer 1

As per the given data in the question,

$\theta=30^\circ$

The weight of the plane =100000N

Thrust force on the plane, along the direction of the flight =120000

So, Additional thrust force is $F_{th}$

$\Rightarrow F_{th}+120000 \sin 30=100000$

$F_{th}=100000-600000=400000N$

Hence, resist force $R=120000\cos30=600000\sqrt{3}N$