Question #102177
A 59.1 kg skier is at rest at the top of a 275 m high run. The slope is inclined at a 22.2º angle relative to horizontal. Assuming that there is no friction between the skis and the snow, how much kinetic energy does the skier have when he/she reaches the bottom of the hill?
1
Expert's answer
2020-02-05T12:29:12-0500
K=mghK=mgh

K=(59.1)(9.8)(275)=159000 J=159 kJK=(59.1)(9.8)(275)=159000\ J=159\ kJ


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