Question #102172
A 9.6 kg block slides down a 9.9 m long ramp inclined at an angle of 30o above the horizontal. At the bottom of the plane, the block transitions to a flat, smooth table that is 5.0 m in length. There is a spring attached to the wall at the end of the flat portion of the track that has spring constant of 246.2 N/m. What is the compression of the spring when the box has stopped moving forward?
1
Expert's answer
2020-02-03T14:22:03-0500

Ep=EsE_p=E_s


Ep=mghE_p=mgh


h=lsin(30°)h=l\cdot \sin(30°)


Ep=mglsin(30°)E_p=mgl\sin(30°)


Es=kx22E_s=\frac{kx^2}{2}


So,


kx22=mglsin(30°)\frac{kx^2}{2}=mgl\sin(30°)


x=2mglsin(30°)k=29.69.89.9sin(30°)243.2=1.96mx=\sqrt{\frac{2mgl\sin(30°)}{k}}=\sqrt{\frac{2\cdot 9.6\cdot 9.8\cdot 9.9\sin(30°)}{243.2}}=1.96 m


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