The moment of inertia of the ball is
I=52mr2 The initial height of the ball is
h=1.9sin77 The initial potential energy is
mgh=mg(1.9sin77) From the conservation of energy:
mgh=0.5mv2+0.5Iω2→mgh=0.5mv2+0.5(0.4mr2)
gh=0.5v2+0.5(0.4v2)=0.7v2
9.81(1.9sin77)=0.7v2
v=5.094sm
t=v2s=5.0942(1.9)=0.746 s
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