Question

A 11.8 kg bowling ball traveling at 13.86 m/s strikes a 3.0 kg bowling pin. The impact slows the bowling ball to 7.60 m/s.



Determine the impulse given to the pin.

Answer 1

$$P=M(v_f-v_i)$$

$$P=11.8(13.86-7.6)=73.9\frac{kg\cdot m}{s}$$