Answer to Question #102037 in Mechanics | Relativity for bjbnl

Question #102037

A 11.8 kg bowling ball traveling at 13.86 m/s strikes a 3.0 kg bowling pin. The impact slows the bowling ball to 7.60 m/s.

Determine the impulse given to the pin.

Expert's answer

"P=M(v_f-v_i)"

"P=11.8(13.86-7.6)=73.9\\frac{kg\\cdot m}{s}"

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