Question #102036
A 9.1 kg bowling ball traveling at 19.1 m/s strikes a 1.6 kg bowling pin. The impact slows the bowling ball to 6.9 m/s.



Determine the velocity given to the pin.
1
Expert's answer
2020-01-31T10:10:47-0500
P=M(vivf)P=M(v_i-v_f)

u=Mm(vivf)u=\frac{M}{m}(v_i-v_f)

u=9.11.6(19.16.9)=69msu=\frac{9.1}{1.6}(19.1-6.9)=69\frac{m}{s}


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