In this case,"h=l-l\\ cos\\theta=l-l\\ cos 37\\degree=\\frac{l}{5}"
As the gravity is acting opposite to direction of ball,
Net work due to gravity"=-(mgh)=-mg\\frac{l}{5}"
Net work done due to applied force"=F\\times s=F\\times l\\ sin\\theta"
As per work energy theorem,
Change in Kinetic energy=Net work done
"\\frac{1}{2}mv^2=Fl\\ sin\\theta-mg\\frac{l}{5}"
Substituting the values,"\\theta=37\\degree,F=14N,l=10 m,m=3\\ Kg" ,
"v=4m\/sec"
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