Speed of the car =65 mi/hour
Radius of the curve = 150 m
angle of inclination "=15^o"
v=23m/sec
Now applying the force balance concept,
"mg \\sin\\theta= \\dfrac{mv^2\\cos15^\\circ}{R}"
"R=\\sqrt{\\dfrac{v^2\\cos15^\\circ}{g\\sin15^\\circ}}=13.8m"
As per the first condition,
"R=\\sqrt{\\dfrac{65\\times 0.44\\times 3.7}{9.8}}=17.37m"
So, here the radius was sufficient to prevent to slipping.
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