Question

A horse canters away from its trainer in a straight line, moving 106 m away in 14.0 s . It then turns abruptly and gallops halfway back in 4.6 s .

Answer 1

Total distance=106m

Time taken to covers this distance =14 sec

So velocity of the horse =$\dfrac{106}{14}=7.57 m/sec$

In the returning, the distance covered $=\dfrac{106}{2}=53m$

times=4.6 sec

So, returning speed =$\dfrac{53}{4.6}=11.52 m/sec$