3. Acceleration [8]
Assume that a car with mass m =1,200 kg accelerates from rest with a constant power (constant change of mv2
energy with time) P = 50. kW. Then the kinetic energy is given by 2 =Pt .
(a) Find the speed as a function of time. [2]
(b) Differentiate the speed to find the acceleration as a function of time. [2]
(c) Assume that the acceleration is limited by the coefficient of friction between the tires and the wet road,
=0.40 . What is the minimum time for the result in part (b) to be valid?
1
Expert's answer
2020-01-20T05:24:48-0500
Solution.
(а)According to the condition of the problem
2mv2=Pt
where m=1200kg is mass of the car; v is the speed of the car; P=50000W is a constant power.
Therefofe
v=m2Pt=1.2×103100×103t=101.2t
(b) Differentiate the speed to find the acceleration as a function of time.
a=dtdv=1.2t5
(c) The force acting on the car must be less than or equal to the friction force
ma≤μN⟹ma≤μmg⟹a≤μg
1.2t5≤0.4×10⟹1.2t1≤0.8⟹1.2t≥1.25
1.2t≥1.5625⟹t≤1.21.5625⟹t≥1.3
Hence the minimum time for the result in part (b) to be valid
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