Answer to Question #101105 in Mechanics | Relativity for Kevin Jude

Question

A cricketer throws a 147g ball by exerting a force of 7.5N for 0.84s. If the launch angle is 39° from horizontal, calculate the range of the ball.

Answer 1

Find initial velocity

$$v_0=\frac{F}{m}t_0$$

It's known problem - throwing the body at an angle to the horizon

$$x=v_0cos(\alpha)t$$ $$y=v_0sin(\alpha)t-\frac{gt^2}{2}$$

From this equation

$$x=\frac{2v_0^2sin(\alpha)cos(\alpha)}{g}$$

Calculating

$$x=\frac{2\cdot (\frac{7.5\cdot 0.84}{0.147})^2 \cdot sin(39)\cdot cos(39)}{10}=183 (m)$$