Question

What will be the acceleration of a 50 kg sledge if the tension in the rope pulling it is 200 N and frictional force is 40 N?

Answer 1

$$a=\frac{F}{m}=\frac{T-F_f}{m}$$

$$a=\frac{F}{m}=\frac{200-40}{50}=3.2\frac{m}{s^2}$$