Question #10097

the density of gold is 19.3 g/ml that of lead is 11.4g/ml that of iron 7.8g/ml, and that of aluminun 2.7 g/ml . a student is given separate samples of three substance A,B, and C along with a graduated cylinder containg 50.0 ml ..of water, Each sample has a mass of 200.0g and the student finds that the volumes of the samples are A , 25.64ml B, 10.36 and C 17.54ml ,what is the identity of each substance

Expert's answer

Due to known formula m=ρVm = \rho * V , were mmass,ρdensity,Vvolumem - \text{mass}, \rho - \text{density}, V - \text{volume} .

Therefore


V=mρV = \frac {m}{\rho}Vgold=20019.3=10.36mlV g o l d = \frac {2 0 0}{1 9 . 3} = 1 0. 3 6 m lVlead=20011.4=17.54mlV l e a d = \frac {2 0 0}{1 1 . 4} = 1 7. 5 4 m lViron=2007.8=25.64mlV i r o n = \frac {2 0 0}{7 . 8} = 2 5. 6 4 m lValuminium=2002.7=74.07mlV a l u m i n i u m = \frac {2 0 0}{2 . 7} = 7 4. 0 7 m l


Answer: "A" is iron, "B" is gold, "C" is lead.

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