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Answer to Question #10092 in Mechanics | Relativity for tammy
Question #10092
gold has a density of 19.3g/ml .suppose you have 100.0 glonkins of gold., what volume in liters will the gold occupy
Expert's answer
A glonkin weighs 0.911 troy ounces.
So 100.0 glonkins = 91.1 troy
ounces.
There are 31.1 grams in a troy ounce, and gold has a density of
19.3
grams / cc. 1 cc = 1 mL.
So,
V = (91.1 oz * 31.1 g/oz) / 19.3 g
/mL = 146.8 mL = 0.1468 L
So 100.0 glonkins = 91.1 troy
ounces.
There are 31.1 grams in a troy ounce, and gold has a density of
19.3
grams / cc. 1 cc = 1 mL.
So,
V = (91.1 oz * 31.1 g/oz) / 19.3 g
/mL = 146.8 mL = 0.1468 L
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