Question

An object slides on the flat ground. It comes to a stop under the influence of friction with a constant acceleration magnitude of 2.45 m/s2. What is the coefficient of kinetic friction between the object and the ground?

Answer 1

From the equation $F=ma\to(1)$ ,

where F is the accelerating force and m is the mass of the object

$F=m*2.45 N$

Also considering the frictional force,

$F'=\mu R\newline F'=\mu*mg\to(2)$

From the balance of forces F'=F applied on the object

$\because$ F=F'

$2.45m=\mu*m*9.81 \newline \mu=0.249$