b) Sketch what happens:
Now simply and correctly applying Newton's second law calculate the acceleration. Point x-axis to the right along the incline and y-axle at 90 degrees to the slope upward:
Ox:F cos27.6∘−μkN−mg sin10.6∘=ma,Oy:F sin27.6∘−mg cos10.6∘+N=0. Hence:
Ox:F cos27.6∘−μkN−mg sin10.6∘=ma,Oy:F sin27.6∘−mg cos10.6∘+N=0. Therefore: N=mg cos10.6∘−F sin27.6∘,a=mF cos27.6∘−μkmN−g sin10.6∘= =mF(cos27.6∘+ sin27.6∘)− −g(μk cos10.6∘− sin10.6∘)==5.10 m/s2.
Comments
Leave a comment