Question #100599

A 1.8 kg otter starts from rest at the top of a

muddy incline 83.5 cm long and slides down

to the bottom in 0.50 s.

What net external force acts on the otter

along the incline?

Answer in units of N.

Expert's answer


By the condition of the problem s=AB=83.5sm=0.835ms=AB=83.5sm=0.835m

from the formula s=at22s=\frac{at^2}{2} we determine the acceleration

a=2st2=20.8350.52=6.68m/s2a=\frac{2s}{t^2}=\frac{2\cdot 0.835}{0.5^2}=6.68{m/s^2}

then we write down Newton’s second law

F=ma=1.86.68=12.024NF=m \cdot a=1.8 \cdot 6.68=12.024N


LATEST TUTORIALS
APPROVED BY CLIENTS