"m=42.4kg"
"a=9.81 m\/s2"
Considering the forces perpendicular to the inclined floor
"mg*cos(10.1)=R+173*sin(26.7)"
solving above equation
"R=331.766 N"
From, F′=μR Where F' is the frictional force
"F\u2032=66.353 N (1)"
Applying "F=ma" along the inclined floor
"173*cos(26.7)-F'-mg*sin(10.1)=ma"
From (1)
"173*cos(26.7)-66.353-42.4*9.81*sin(10.1)=42.4a"
Solving above equation
"a=0.3598 m\/s2"
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