The work to lift up block of mass "M"onto a benchtop surface that is "H" above the floor is "A=M\\cdot g\\cdot H" where "g=9.8 \\frac{m}{s^2}" is acceleration of gravity. The difference between two work will be "\\delta A= M_2\\cdot gH - M_1\\cdot gH = (M_2 - M_1)gH"
"\\delta A=(4.7 - 3.2)kg\\cdot 9.8\\frac{m}{s^2}\\cdot 0.75 m=11.0 J"
Answer: The work of lifting block B on the benchtop surface is more than when lifting block A by 11.0 J.
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