9.
(i)
v2−u2=2as=2×5×300=3000 ......(1)
also,
v−u=at=5×20=100 ...(2)
solving (1) and (2)
We get
v=65 m/sec and u=−35 m/sec
(ii)
s=21at2=0.5×5×202=1000 m
(iii)
v=u+at=−35+5×10=15 m/sec
10.
(i)
change in momentum = m(v2−v1)=0.080×(−39−25)=−5.12 N m/sec
(ii)
average force needed = ΔtΔP=0.0205.12=256 N
(iii)
If the mass of ball increses then william will have to apply more force to return it due to which he can damage his shoulder.
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