Question #90604
How would psi_bar gamma_mu psi transform under parity transformation?
1
Expert's answer
2019-06-06T10:09:23-0400
P(ψˉγμψ)=ψˉγ0γμγ0ψ=(ψˉγμψ)ϵμP( \bar{\psi} \gamma_\mu \psi) =\bar{\psi} \gamma_0 \gamma_\mu \gamma_0 \psi= (\bar{\psi} \gamma_\mu \psi) \epsilon^\mu

where

ϵμ=1 for μ=0 and1 forμ=1,2,3\epsilon^\mu =1\space for \space \mu=0 \space and -1\space for \mu = 1,2,3


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