Question

A ball hits a wall horizontally at 6m/s, it rebounds horizontally at 4.4 m/s, the ball is in contact with the wall for 0.04s, what is the acceleration?

Answer 1

Answer on Question #67806 - Physics | Field Theory

A ball hits a wall horizontally at $6\mathrm{m/s}$, it rebounds horizontally at $4.4\mathrm{m/s}$, the ball is in contact with the wall for 0.04s, what is the acceleration?

Solution

The acceleration of a ball by definition

$$a = \frac {| \Delta \vec {v} |}{\Delta t}.$$

Change of velocity

$$| \Delta \vec {v} | = 6 - (- 4. 4) = 1 0. 4 \frac {\mathrm {m}}{\mathrm {s}}.$$

Thus

$$a = \frac {1 0 . 4}{0 . 0 4} = 2 6 0 \frac {\mathrm {m}}{\mathrm {s} ^ {2}}.$$

Answer: $260\frac{\mathrm{m}}{\mathrm{s}^2}$

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