Question #65071

A parallel plate capacitor has an electric field of 20 N/C and a plate area of 0.5 m^2. What is the total charge on the capacitor?

Expert's answer

Answer on Question #65071-Physics - Field Theory

Question

A parallel plate capacitor has an electric field of 20N/C20\,\mathrm{N/C} and a plate area of 0.5m20.5\,\mathrm{m^2}. What is the total charge on the capacitor?

Answer

The total charge on the capacitor


Q=CU,Q = C U,U=Ed,U = E d,C=ε0Ad,C = \frac{\varepsilon_0 A}{d},Q=ε0AdEd=ε0AE=8.85×1012×0.5×20=88.5×1012C=88.5pCQ = \frac{\varepsilon_0 A}{d} E d = \varepsilon_0 A E = 8.85 \times 10^{-12} \times 0.5 \times 20 = 88.5 \times 10^{-12} \,\mathrm{C} = 88.5 \,\mathrm{p\,C}


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