Question #52086

Heat can be defined as------------------------
the change in temperature of a body
the flow of temperature from one body to another
energy that flows from place to place as a result of the difference in temperature between them
the measure of hotness or coolness of a body

11 Two bodies may be said to be in thermal equilibrium if
the bodies are thermally insulated from one another
the bodies are not in thermal equlibrium with another body
if one body loses heat to the other
if there not net flow of heat between the two bodies two bodies in thermal contact

12 Heat capacity has units as
J/kg.K
J/mol.K
J.ohm/sec.K2
W/m.K

13 An engine absorbs 2000J of heat from a hot reservoir and expels 750J to a cold reservoir during each operating cycle. What is the power output of the engine if each cycle lasts for 0.5 seconds?
750W
1750W
3000W
2500W

Expert's answer

Answer on Question #52086, Physics, Field Theory

Heat can be defined as---

the change in temperature of a body

the flow of temperature from one body to another

energy that flows from place to place as a result of the difference in temperature between them

the measure of hotness or coolness of a body

Answer: energy that flows from place to place as a result of the difference in temperature between them

11 Two bodies may be said to be in thermal equilibrium if

the bodies are thermally insulated from one another

the bodies are not in thermal equilibrium with another body

if one body loses heat to the other

if there not net flow of heat between the two bodies two bodies in thermal contact

Answer: if there not net flow of heat between the two bodies two bodies in thermal contact

12 Heat capacity has units as

J/kg.K

J/mol.K

J.ohm/sec.K2

W/m.K

Answer: J/kg.K

13 An engine absorbs 2000J of heat from a hot reservoir and expels 750J to a cold reservoir during each operating cycle. What is the power output of the engine if each cycle lasts for 0.5 seconds?

750W

1750W

3000W

2500W

Solution

The work performed by the engine is A=2000J750J=1250JA = 2000J - 750J = 1250J.

The power output of the engine if each cycle is P=A/t=1250J/0.5s=2500WP = A / t = 1250J / 0.5s = 2500W

Answer: P=2500WP = 2500W

http://www.AssignmentExpert.com/


Need a fast expert's response?

Submit order

and get a quick answer at the best price

for any assignment or question with DETAILED EXPLANATIONS!

LATEST TUTORIALS
APPROVED BY CLIENTS