Question #52081

The statement "Heat lost by hot object is equal to heat gained by cold object" another way of expressing the law of conservation of ---------------------
charge
angular momentum
energy
momentum

15 Which of the following does NOT determine the amount of internal energy an object has?
temperature
amount of material
type of material
shape of the object

16 Calculate the work done against external atmospheric pressure when 1 g of water changes to
1672cm3
of steam. Take the atmospheric pressure as
1.013×105Nm−2
169.3 J
342.4 J
226.2 J
143.5 J

Expert's answer

Answer on Question #52081-Physics-Field Theory

The statement "Heat lost by hot object is equal to heat gained by cold object" another way of expressing the law of conservation of ---

charge

angular momentum

energy

momentum

Answer: energy.

15 Which of the following does NOT determine the amount of internal energy an object has?

temperature

amount of material

type of material

shape of the object

Answer: shape of the object.

16 Calculate the work done against external atmospheric pressure when 1 g of water changes to 1672cm3 of steam. Take the atmospheric pressure as 1.013×105Nm−2

169.3 J

342.4 J

226.2 J

143.5 J

Solution


W=P(VsteamVwater)=Pm(1ρsteam1ρwater)=1.013105Nm2103kg(1.6720.001)m3kg=169.3J.W = P(V_{\text{steam}} - V_{\text{water}}) = Pm\left(\frac{1}{\rho_{\text{steam}}} - \frac{1}{\rho_{\text{water}}}\right) = 1.013 \cdot 10^{5} \, \text{Nm}^{-2} \cdot 10^{-3} \, \text{kg} \, (1.672 - 0.001) \, \frac{\text{m}^3}{\text{kg}} = 169.3 \, \text{J}.


Answer: 169.3 J.

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