starting from rest, a train is uniformly accelerated and reaches a velocity of 20km/h after 15cesconds. what is its acceleration
Answer
Acceleration is
a=vt=200003600∗15=0.37m/s2a=\frac{v}{t}\\=\frac{20000}{3600*15}\\=0.37m/s^2a=tv=3600∗1520000=0.37m/s2
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