Answer to Question #307456 in Field Theory for Anne

Question #307456

 Find the magnitude of an electron's electric field if the field itself is 50cm away from it.


1
Expert's answer
2022-03-07T11:43:40-0500

he electric field due the point charge


E=kqr2E=k\frac{q}{r^2}E=91091.610190.52=5.76109V/mE=9*10^9*\frac{1.6*10^{-19}}{0.5^2}=5.76*10^{-9}\:\rm V/m

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