Question #296080

A block of mass 4kg is on the point of slipping down a plane inclined at an angle of 30° to the horizontal.What force parallel to the plane will just move it up the plane?


Expert's answer

Solution

Inclined angle

θ=30°\theta=30°

Mass m=4Kg



force parallel to the plane will just move it up the plane is given by

F=mg sin θ\theta

=4×9.81×sin30°=19.62N=4\times9.81\times sin30°\\=19.62N


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