Answer to Question #287305 in Field Theory for okwy

Question

a student eat a dinner containing 3.0 x 106J of energy. He wishes to do an equivalent amount of work in a near by gym by lifting a 60kg object.How many times

Answer 1

Solution

Let he raise the object (mass) at height h .

Using work energy conservation. Let he gym n times h=2m

nMgh=w (work)

$n60\times9.81\times 2=3\times10^6\\n$

$=\frac{3000000}{1200\times9.81}\\=52.57m\\=26.52m$