Question

An electron experiences a force f given as (f=3.2i ---2.7j)×10^-13N when passing through a magnetic field B=0.72kJ. calculate the velocity of the electron?. Take the electron charge Q=1.5×10^-19cou.

Answer 1

$$4.2\cdot10^{-13}=(1.5\cdot10^{-19})(0.72)v\\v=3.9\cdot10^{6}\frac{m}{s}$$