Question

Two parallel plates at a distance of 0.008m apart are maintained at a potential difference of 600v with the negative plate earthed, calculate the electric field strength around the plates.

Answer 1

The electric field strength around the plates can be found as follows:

$$E=\dfrac{V}{d}=\dfrac{600\ V}{0.008\ m}=7.5\times10^4\ \dfrac{V}{m}.$$