an electron released from rest in uniform electric field of magnitude e=220 n/c and gains speed. find magnitude of force applied to it
The field of magnitude EEE acts on the point charge qqq with force F=qEF = q EF=qE. Therefore, F=1.6⋅10−19C⋅220NC≈3.5⋅10−17NF = 1.6 \cdot 10^{-19} C\cdot 220 \frac{N}{C} \approx 3.5 \cdot 10^{-17} NF=1.6⋅10−19C⋅220CN≈3.5⋅10−17N.
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