Question #217882
A 500g uniform sphere of 7.0cm radius spins at 30 rev/s on an axis through it's centre. Find it's, a) rotational kinetic energy, b)angular momentum, C) radius of gyration
1
Expert's answer
2021-07-16T08:51:38-0400

Given:

m=0.5kgm=0.5\:\rm kg

n=30rev/sn=30\:\rm rev/s

R=0.07mR=0.07\:\rm m

(a)

Ek=Iω22=2/5mR2(2πn)22=4/5π2mR2n2E_k=\frac{I\omega^2}{2}=\frac{2/5mR^2*(2\pi n)^2}{2}=4/5\pi^2mR^2n^2

=4/5π20.50.072302=17.4J=4/5\pi^2*0.5*0.07^2*30^2=17.4\:\rm J

(b)

L=Iω=2/5mR22πn=4/5πmR2nL=I\omega=2/5mR^2*2\pi n=4/5\pi mR^2n

=4/5π0.50.07230=0.37kgm2/s=4/5\pi*0.5*0.07^2*30=0.37\:\rm kg\cdot m^2/s

(c)

r=Im=2R25r=\sqrt{\frac{I}{m}}=\sqrt{\frac{2R^2}{5}}

=2/50.07=0.044m=4.4cm=\sqrt{2/5}*0.07=0.044\:\rm m=4.4\:\rm cm


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