Answer
By putting unit of each quantity in given formula
"\\frac{m^3}{sec}=(\\frac{N}{m^2}\u00d7m^6) \/[c ]m"
[c] represents unit of "c"
So
"[c]=\\frac{N\u00d7sec\u00d7m^6}{m^2\u00d7m^3\u00d7m}"
"[c]=\\frac{N\u00d7sec\u00d7m^6}{m^6}"
"[c]=N-sec"
Its represent impulse.
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