Question

Three equal charges of -3.2x10^-6 C are situated at the corners of a triangle of side 3 m. Find the electric field at the center of the triangle.

Answer 1

Answer

Magnitude of electric field due to each charge will be equal so

$E=\frac{(9\times10^9)(3.2\times10^{-6})}{(\frac{3}{\sqrt{2}})^2}$

$E=6.4\times10^3N/C$

Net electric field at center

$E_{net}=6.4\times10^3(2cos30°-1) \\E_{net}=4.68\times10^{3}N/C$