Question

A golfer wants to drive a golf ball a distance of 310yards (283m).  If the 4-wood launches the ball at 21° above the horizontal, what must the initial speed of the ball be in order to achieve the required distance?

Answer 1

Answer

Vertical velocity can be obtain as

$(vsin21°)t-\frac{1}{2}(9.8)t=0\\ vsin21°-4.9t=0\quad... Eq. 1$

Horizontal velocity can be obtain as

$vcos21°t=283\\t=\frac{303.1}{v}$

By eq. 1

$0.36v-\frac{1485.2}{v}=0\\v=64.23m/s$