Answer to Question #187784 in Field Theory for Rahul

Question #187784

A body with an initial velocity of 3 ms -1moves with an acceleration of 2 ms -2, then the distance travelled in the 4 the second is

Expert's answer

Answer

Using newton equation of motion

$S=ut+0.5at^2\\=3\times4+0.5\times2\times4^2\\=28m$

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