Compute the electric potential from a source charge of -2.33 ×10^-13 C if a test charge is 6.45 × 10^-15m away from it
Solution
Electric potential due to point charge is given
"V=\\frac{kq}{r}\\\\=\\frac{9\\times10^9\\times(-2.33\\times10^{-13})}{6.45\\times10^{-15})}\\\\=-3.25\\times10^{11}volts"
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