A negatively charged droplet of mass 4.5x10 -3ng remains balanced in the electric field between parallel horizontal plates which are 10mm apart if the potentional difference between the plates is 1000 V calculate the charge on the droplet (g =9.8 -2)
Answer
Using formula
"Charge=\\frac{Mgd}{V}\\\\=\\frac{4.5\\times10^{15}\\times9.8\\times0.010}{1000}\\\\=44.1\\times10^{10}C"
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