A point charge of -10µC is located at x=-4cm. Find the magnitude and direction of the Electric field at the origin.
Answer
Electric field due to point charge is given
"E=\\frac{kq}{r^2}"
So electric field by
-10µC on at origin
"E=\\frac{9\\times10^9\\times10\\times10^{-6}}{0.04\\times0.04}(-i) \\\\=0.56\\times10^8(-i) N\/C."
In -x axis direction.
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