Question

A point charge of -10µC is located at x=-4cm. Find the magnitude and direction of the Electric field at the origin.

Answer 1

Answer

Electric field due to point charge is given

$E=\frac{kq}{r^2}$

So electric field by

-10µC on at origin

$E=\frac{9\times10^9\times10\times10^{-6}}{0.04\times0.04}(-i) \\=0.56\times10^8(-i) N/C.$

In -x axis direction.