Question

An object having a net charge of 20μC is placed in a uniform electric field of 1000N/C directed vertically. What is the mass of this object?

Answer 1

Answer

In case of equilibrium

Mass is given

$M=\frac{qE}{g}$

Where

q=20$\times10^{-6}C$

E=1000N/C

$M=\frac{20\times10^{-6}\times1000}{9.8}=0.196Kg$