Two small conducting balls of identical mass m and charge q hang from non-conducting rope of length L Assume that Ɵ is very small tanƟ = sinƟ. Find an expression for the equilibrium separation x of the balls.
Answer
Tension in rope
By vertical equilibrium
"T=\\frac{mg}{cos\\theta}"
By equilibrium
"\\frac{kq^2}{L^2sin^2\\theta}=Tsin{\\theta}"
And
"\\frac{kq^2}{L^2sin^2\\theta}=\\frac{mg}{cos\\theta}sin{\\theta}"
"\\frac{kq^2}{4(L^2sin^2\\theta)}=mgtan{\\theta}"
Comments
Leave a comment