Question #169685

Three charges are sitting at the corners of an equilateral triangle. If 𝑞1 = 𝑞3 = 10 𝜇𝐶 , 𝑞2 = 5 𝜇𝐶 and the length of each side is 20 cm, find the force experienced by charge 𝑞2 in unit-vector notation and magnitude-angle notation.


1
Expert's answer
2021-03-09T15:29:29-0500
Fx=0 NF=Fy=2Fsin60F=Fy=2(9109)(10106)(5106)0.22sin60=19.5 NF_x=0\ N\\F=F_y=2F'\sin{60} \\F=F_y=2(9\cdot10^9)\frac{(10\cdot10^{-6})(5\cdot10^{-6})}{0.2^2}\sin{60}=19.5\ N

F=19.5 NjF=19.5 N 90°\vec{F}=19.5\ N \vec{j}\\ \vec{F}=19.5\ N \text{ 90}\degree


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