Answer to Question #169655 in Field Theory for Biniyam

Question

when two vectors acting in the same direction are added tge give the resultant of 70 unit when they act in perpendicular direction they give a resultant 50 unit what will be the sum of 2 units if they were acting in the opposite direction

Answer 1

$$a+b=70\\\sqrt{a^2+b^2}=50\\\sqrt{a^2+(70-a)^2}=50\\a=30\\b=40$$

Thus,

$$b-a=40-30=10$$