Answer to Question #163868 in Field Theory for Mary Ann Castillejo

Question #163868

a plane lands at a speed of 68 m/s and slows down at a rate 0f 4 m/s^2. How much runway is needed to stop the plane?


1
Expert's answer
2021-02-15T17:03:34-0500

Answer

By applying third equation of motion

v2=u2+2asv^2=u^2+2as

When plane will stop then

v=0m/sv=0m/s

Acceleration

a=4m/s2a=-4m/s^2

Initial velocity

u=68m/su=68m/s


So by putting value

02=6822(4)(s)s=6828s=578m0^2=68^2-2(4) (s) \\s=\frac{68^2}{8}\\s=578m

So 578m runway is required.



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