Answer to Question #163647 in Field Theory for Bawe

Question

The Earth’s orbit is of mean radius 1.50 x 10¹¹ m and the Earth’s year is 365 days long.

(i)The mean radius of the orbit of Mercury is 5.97 x 10¹⁰ m. Calculate the length of Mercury’s year.

(ii) Neptune orbits the Sun once every 165 Earth year.

    Calculate the ratio: distance from Sun to Neptune / distance from Sun to Earth

Answer 1

Answers

Time period of mercury can be given as

$T_m=\sqrt{\frac{R_m^3T_e^2}{R_e^3}}$

$T_m=\sqrt{\frac{(5.97\times10^{10})^3(365^2)}{(1.50\times10^{11})^3}}$

$T_m=23days \quad of\quad earth$