Answer
Let us suppose
the planets are moving in circular orbits.
So gravitational force can be written as
F=GMmr2F=\frac{GMm}{r^2}F=r2GMm ...... 1
Force is given as
F=maF=maF=ma ...... 2
Using both equation
F=ma=GMmr2F=ma=\frac{GMm}{r^2}F=ma=r2GMm
a=GMr2a=\frac{GM}{r^2}a=r2GM
So acceleration
a∝1r2a\propto\frac{1}{r^2}a∝r21
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