Question

The free fall acceleration on the surface of the moon is about one-sixth that on the surface of the Earth. The radius of the moon is about 0.250Re where Re = 6.37 x 10^6 m. Find the ratio of their average densities, pMoon/pEarth.

Answer 1

Answer

Relationship between radius density and acceleration is given by as

$\rho\propto g/R$

$\frac{\rho_{moon}}{\rho_{Earth}}=\frac{gR}{6g(0.250)R}=2/3$