find electric field at center of square q=11.8 nC AND a=5.20cm
Answer
If chage q is at every corner of the squre then electric field at center can be given as
E→net=E→1+E→2+E→3+E→4\overrightarrow E_{net}=\overrightarrow E_1+\overrightarrow E_2+\overrightarrow E_3+\overrightarrow E_4Enet=E1+E2+E3+E4
All charge are equal in magnitude and at equal distance from center of square
So
E→1=−E→2E→3=−E→4\overrightarrow E_1=-\overrightarrow E_2\\\overrightarrow E_3=-\overrightarrow E_4E1=−E2E3=−E4
Enet=0V/mE_{net}=0V/mEnet=0V/m
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