Solution
When a particle is falling free from height h then it's initial velocity is u=0
Here acceleration is gravitation acceleration g, let velocity is v at ground
Then using third equation of motion
v2=u2+2asv^2=u^2+2asv2=u2+2as
v2=0+2ghv^2=0+2ghv2=0+2gh
v=2ghv=\sqrt{2gh}v=2gh
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